Option 1 : 1

**Calculation:**

⇒ Let Sh -— Shailendra,

⇒ Su — Surendra be soldiers,

⇒ Ch -— Chetan,

⇒ Ck – Chetak be charioteers,

⇒ D — Dinesh — Doctor.

⇒ Sh at only extreme places

⇒ (Hence Sh — 1 or 5 ) and since Su can’t stand at least just before Sh, this place has to be taken by a charioteer.

⇒ Hence a charioteer always stands next to a doctor. Hence, P = 1.

__Additional Information__

⇒ The number of outcomes favorable to A is denoted by n(A) The total number of outcomes in sample space is denoted by n(S).

Hence, the formula becomes

P(A) = n(A)/n(S).

⇒ The probability of an event can vary between 0 to 1, i.e. 0 ≤ p ≤ 1.

⇒ Probability can never be negative.

⇒ Probability of occurrence of an event = 1 – (Probability that it doesn’t occur).